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← Problem 69: (2003 AMC 10A, 19; 2003 AMC12A 15) →
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Problem 69: (2003 AMC 10A, 19; 2003 AMC12A 15)
A semicircle of diameter $1$ sits at the top of a semicircle of diameter $2$, as shown. The shaded area inside the smaller semicircle and outside the larger semicircle is called a lune. Determine the area of this lune. $\mathrm{(A) \ } \frac{1}{6}\pi-\frac{\sqrt{3}}{4}\qquad$ $ \mathrm{(B) \ } \frac{\sqrt{3}}{4}-\frac{1}{12}\pi\qquad$ $ \mathrm{(C) \ } \frac{\sqrt{3}}{4}-\frac{1}{24}\pi\qquad$ $ \mathrm{(D) \ } \frac{\sqrt{3}}{4}+\frac{1}{24}\pi\qquad$ $ \mathrm{(E) \ } \frac{\sqrt{3}}{4}+\frac{1}{12}\pi$
Solution
Exercise 69: Solution
A semicircle of diameter $2\sqrt{2}$ sits at the top of a semicircle of diameter $4$. The shaded area inside the smaller semicircle and outside the larger semicircle is called a lune. Determine the area of this lune.
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