Problem 4

{{searchResults.length}} results for “{{searchWords}}” No results found for “{{searchWords}}” × back to contents

§{{x[0]}} {{x[1]}}

Table of Contents

Problem 4: (2018 AMC 10A, 13; 2018 AMC12A 11)

A paper triangle with sides of lengths $3,4,$ and $5$ inches, as shown, is folded so that point $A$ falls on point $B$. What is the length in inches of the crease?

$\textbf{(A) } 1+\frac12 \sqrt2 \qquad$ $ \textbf{(B) } \sqrt3 \qquad$ $ \textbf{(C) } \frac74 \qquad$ $ \textbf{(D) } \frac{15}{8} \qquad$ $ \textbf{(E) } 2$

Solution

Exercise 4: Solution

A paper triangle $ABC$ has a right angle at $C$, with $AC=12$ inches and $BC=5$ inches (so $AB=13$ inches). The triangle is folded so that point $A$ falls exactly on point $B$. What is the length in inches of the crease?

Search Go to Prev Next

Contact Us