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Problem 218: (2018 AMC 12a, 20)
Triangle $ABC$ is an isosceles right triangle with $AB=AC=3$. Let $M$ be the midpoint of hypotenuse $\overline{BC}$. Points $I$ and $E$ lie on sides $\overline{AC}$ and $\overline{AB}$, respectively, so that $AI>AE$ and $AIME$ is a cyclic quadrilateral. Given that triangle $EMI$ has area $2$, the length $CI$ can be written as $\frac{a-\sqrt{b}}{c}$, where $a$, $b$, and $c$ are positive integers and $b$ is not divisible by the square of any prime. What is the value of $a+b+c$? $\textbf{(A) }9 \qquad$ $ \textbf{(B) }10 \qquad$ $ \textbf{(C) }11 \qquad$ $ \textbf{(D) }12 \qquad$ $ \textbf{(E) }13 \qquad$
Solution
Exercise 218: Solution
Triangle $ABC$ is an isosceles right triangle with $AB=AC=4$. $M$ is the midpoint of $\overline{BC}$; $I,E$ lie on $\overline{AC},\overline{AB}$ so that $AI>AE$ and $AIME$ is cyclic. Given $[EMI]=3$, $CI=a-\sqrt b$ for positive integers $a,b$. What is $a+b$?
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