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Theorem 53
Given a quadrilateral $ABCD, AB=a, BC=b, CD=c, DA=d$, let $s=\frac{a+b+c+d}2$, the area formula is $$[ABCD]=\sqrt{(s-a)(s-b)(s-c)(s-d)-abcd\cos^2(\frac{B+D}2)}$$
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