Sign Up
Login
Test sets
My results
Contact Us
Logout
Sign in
←
Theorem 18
→
« Prev
Next »
Search
Go to
{{searchResults.length}} result
s
for “{{searchWords}}”
No results found for “{{searchWords}}”
× back to contents
§{{x[0]}}
{{x[1]}}
Table of Contents
Browse by chapter, year or number
Similar Triangles
areas
pythagoreanTheorem
circles
quadrilaterals
threeDimensionalGeometry
trigonometry
conic
miscellaneous
exercises solutions
Theorem 18
For a right triangle $ABC$, with $\angle C=90^\circ$, then we have $ AC^2+BC^2=AB^2$.
← Back to Problem 114
Search
Go to
Prev
Next
×
Contact Us
Send
Thanks! Your message has been sent.