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Problem 63: (2012 AMC 10A, 18; 2012 AMC12A 14)
The closed curve in the figure is made up of $9$ congruent circular arcs each of length $\frac{2\pi}{3}$, where each of the centers of the corresponding circles is among the vertices of a regular hexagon of side $2$. What is the area enclosed by the curve? $\textbf{(A)}\ 2\pi+6\qquad$ $\textbf{(B)}\ 2\pi+4\sqrt{3}\qquad$ $\textbf{(C)}\ 3\pi+4\qquad$ $\textbf{(D)}\ 2\pi+3\sqrt{3}+2\qquad$ $\textbf{(E)}\ \pi+6\sqrt{3}$
Solution
Exercise 63: Solution
Four circles of radius $1$ have their centers at the vertices of a square with side length $2$. The inward-facing quarter-circle arcs joining the midpoints of adjacent sides form the closed curve shown. What is the area enclosed by the curve?
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