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Problem 360: (2013 AMC 12a, 12)
The angles in a particular triangle are in arithmetic progression, and the side lengths are $4,5,x$. The sum of the possible values of x equals $a+\sqrt{b}+\sqrt{c}$ where $a, b$, and $c$ are positive integers. What is $a+b+c$? $\textbf{(A)}\ 36\qquad$ $\textbf{(B)}\ 38\qquad$ $\textbf{(C)}\ 40\qquad$ $\textbf{(D)}\ 42\qquad$ $\textbf{(E)}\ 44$
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Exercise 360: Solution
The angles in a particular triangle are in arithmetic progression, and the side lengths are $6,7,x$. The sum of the possible values of $x$ equals $a+\sqrt b+\sqrt c$, where $a,b,c$ are positive integers. What is $a+b+c$?
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