A triangle has area $30$, one side of length $10$, and the median to that side of length $9$. Let $\theta$ be the acute angle formed by that side and the median. What is $\sin{\theta}$? $\textbf{(A)}\ \frac{3}{10}\qquad$ $\textbf{(B)}\ \frac{1}{3}\qquad$ $\textbf{(C)}\ \frac{9}{20}\qquad$ $\textbf{(D)}\ \frac{2}{3}\qquad$ $\textbf{(E)}\ \frac{9}{10}$