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Problem 330: (2012 AMC 10b, 23)
A solid tetrahedron is sliced off a wooden unit cube by a plane passing through two nonadjacent vertices on one face and one vertex on the opposite face not adjacent to either of the first two vertices. The tetrahedron is discarded and the remaining portion of the cube is placed on a table with the cut surface face down. What is the height of this object? $\textbf{(A)}\ \frac{\sqrt{3}}{3}\qquad$ $\textbf{(B)}\ \frac{2\sqrt{2}}{3}\qquad$ $\textbf{(C)}\ 1\qquad$ $\textbf{(D)}\ \frac{2\sqrt{3}}{3}\qquad$ $\textbf{(E)}\ \sqrt{2}$
Solution
Exercise 330: Solution
A solid tetrahedron is sliced off a wooden rectangular solid measuring $1\times2\times3$ by the plane through the three vertices adjacent to one vertex $A$ of the solid. The tetrahedron is discarded, and the remaining solid is placed on a table with the cut face down. What is the height of this solid?
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