In the figure shown below, $ABCDE$ is a regular pentagon and $AG=1$. What is $FG+JH+CD$?
$\textbf{(A) } 3 \qquad$ $\textbf{(B) } 12-4\sqrt5 \qquad$ $\textbf{(C) } \dfrac{5+2\sqrt5}{3} \qquad$ $\textbf{(D) } 1+\sqrt5 \qquad$ $\textbf{(E) } \dfrac{11+11\sqrt5}{10}$