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← Problem 160: (2006 AMC 10a, 14; 2006 AMC12a, 12) →
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Problem 160: (2006 AMC 10a, 14; 2006 AMC12a, 12)
A number of linked rings, each 1 cm thick, are hanging on a peg. The top ring has an outside diameter of 20 cm. The outside diameter of each of the other rings is 1 cm less than that of the ring above it. The bottom ring has an outside diameter of 3 cm. What is the distance, in cm, from the top of the top ring to the bottom of the bottom ring? $\mathrm{(A)}\ 171\qquad$ $\mathrm{(B)}\ 173\qquad$ $\mathrm{(C)}\ 182\qquad$ $\mathrm{(D)}\ 188\qquad$ $\mathrm{(E)}\ 210$
Solution
Exercise 160: Solution
A number of linked rings, each $1$ cm thick, hang on a peg. The top ring has outside diameter $30$ cm, each subsequent ring's outside diameter is $1$ cm less, and the bottom ring has outside diameter $5$ cm. What is the distance from the top of the top ring to the bottom of the bottom ring?
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