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Exercise 410
In a triangle with integer side lengths, one side is three times as long as a second side, and the length of the third side is $20$. What is the greatest possible perimeter of the triangle?
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Solution
Let sides be $x,3x,20$. Triangle inequality: $x+20>3x\Rightarrow x<10$; $x+3x>20\Rightarrow x>5$.
So $x\in\{6,7,8,9\}$; greatest perimeter at $x=9$: sides $9,27,20$, perimeter $=\boxed{56}$.
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