In rectangle $ADEH$, $AB=CD=HG=FE=2$, $BC=GF=1$, and $DE=AH=3$. Segments $AF$, $DG$, $HC$, and $EB$ intersect to form quadrilateral $WXYZ$, as shown. What is the area of $WXYZ$?
Use coordinates $H=(0,0)$, $A=(0,3)$, $D=(5,3)$, and $E=(5,0)$; the specified side divisions give $B=(2,3)$, $C=(3,3)$, $G=(2,0)$, and $F=(3,0)$.
The four segments have equations $AF:y=3-x$, $DG:y=x-2$, $HC:y=x$, and $EB:y=5-x$. Their intersections are $W=(5/2,5/2)$, $X=(7/2,3/2)$, $Y=(5/2,1/2)$, and $Z=(3/2,3/2)$.
The diagonals $WY$ and $XZ$ are perpendicular and each has length $2$, so $$[WXYZ]=\frac12\cdot2\cdot2=2.$$